giúo mình giải chi tiết vs ạ

Đáp án `+` Giải thích các bước giải:

`1) (x + 1/2)^2 = 1/16`

`(x + 1/2)^2 = (1/4)^2 = (-1/4)^2`

`=> {(x + 1/2 = 1/4),(x + 1/2 = -1/4):}`

`=> {(x = -1/4),(x = -3/4):}`

Vậy `x \in {-1/4 ; -3/4}`

`\text{}`

`2) (x - 3/2)^2 = 9/16`

`(x - 3/2)^2 = (3/4)^2 = (-3/4)^2`

`=> {(x - 3/2 = 3/4),(x - 3/2 = -3/4):}`

`=> {(x = 9/4),(x = 3/4):}`

Vậy `x \in {9/4 ; 3/4}`

`\text{}`

`3) (x + 2/5)^2 = 9/16`

`(x + 2/5)^2 = (3/4)^2 = (-3/4)^2`

`=> {(x + 2/5 = 3/4),(x + 2/5 = -3/4):}`

`=> {(x = 7/20),(x = -23/20):}`

Vậy `x \in {7/20 ; -23/20}`

`\text{}`

`4) (x - 4/7)^2 = 1/49`

`(x - 4/7)^2 = (1/7)^2 = (-1/7)^2`

`=> {(x - 4/7 = 1/7),(x - 4/7 = -4/7):}`

`=> {(x = 5/7),(x = 3/7):}`

Vậy `x \in {5/7 ; 3/7}`

`\text{}`

`5) (x - 5/6)^2 = 1/36`

`(x - 5/6)^2 = (1/6)^2 = (-1/6)^2`

`=> {(x - 5/6 = 1/6),(x - 5/6 = -1/6):}`

`=> {(x = 1),(x = 2/3):}`

Vậy `x \in {1 ; 2/3}`

`\text{}`

`6)` `(2x + 3)^2 = 25`

`(2x + 3)^2 = 5^2 = (-5)^2`

`=> {(2x + 3 = 5),(2x + 3 = -5):}`

`=> {(2x = 2),(2x = -8):}`

`=> {(x = 1),(x = -4):}`

Vậy `x \in {1 ; -4}`

`\text{}`

`7) 31/36 - (1/3 - x)^2 = 5/6`

`(1/3 - x)^2 = 1/36`

`(1/3 - x)^2 = (1/6)^2 = (-1/6)^2`

`=> {(1/3 - x = 1/6),(1/3 - x = -1/6):}`

`=> {(x = 1/6),(x = 1/2):}`

Vậy `x \in {1/6 ; 1/2}`

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