Cho e cách giải nhanh vs ạ. Giải thích nữa nha

Đáp án:

`14.A`

`15.C`

`16.B`

Giải thích các bước giải:

`14)`

`0,8g//mL=0,8kg//L`

`V_{C_2H_5OH}={10000.96}/{100}=9600(L)`

`->m_{C_2H_5OH}=9600.0,8=7680(kg)`

`(C_6H_{10}O_5)_n->2nC_2H_5OH`

`162n->92n(kg)`

`x←7680(kg)`

`->x=m_{(C_6H_{10}O_5)_n\ t t}={7680.162n}/{92n}\approx 13523,5(kg)`

`->m_{\text{mùn cưa}}={13523,5}/{35\%.50\%}\approx 7728(kg)=77,28(tấn)`

`15)`

`0,8g//mL=0,8kg//L`

`m_{(C_6H_{10}O_5)_n\ t t}=1.10^{3}.85\%.40\%=340(kg)`

`(C_6H_{10}O_5)_n->2nC_2H_5OH`

`162n->92n(kg)`

`340->x(kg)`

`->x=m_{C_2H_5OH\ t t}={340.92n}/{162n}\approx 193,1(kg)`

`->V_{C_2H_5OH\ t t}={193,1}/{0,8}=241,375(L)`

`->V_r={241,375.100}/{95}\approx 254,06(L)`

`16)`

`V_{C_2H_5OH}={1.10^{3}.40}/{100}=400(mL)`

`->m_{C_2H_5OH\ t t}=400.0,8=320(g)`

`C_6H_{12}O_6->2C_2H_5OH`

`180->92(g)`

`x←320(g)`

`->x=m_{C_6H_{12}O_6\ t t}={320.180}/{92}\approx 626,09(g)`

`->m_{C_6H_{12}O_6\ l t}={626,09}/{45\%}\approx 1390(g)`