Đáp án `+` Giải thích các bước giải:

`7) (6^15 . 9^10)/(3^34 . 2^13)`

`= ((2 . 3)^15 . (3^2)^10)/(3^34 . 2^13)`

`= (2^15 . 3^15 . 3^20)/(3^34 .2^13)`

`= (2^15 . 3^35)/(3^34 . 2^13)`

`= 2^2 . 3`

`= 4 . 3`

`= 12`

``

`8) (9^2 . 2^11)/(16^2 . 6^3)`

`= ((3^2)^2  . 2^11)/((2^4)^2 . (2 . 3)^3)`

`= (3^4 . 2^11)/(2^8 . 2^3 . 3^3)`

`= (3^4 . 2^11)/(2^11 . 3^3)`

`= 3`

``

`9) (4^5 . 9^4)/(8^3 . 27^3)`

`= ((2^2)^5 . (3^2)^4)/((2^3)^3 . (3^3)^3)`

`= (2^10 . 3^8)/(2^9 . 3^9)`

`= 2/3`