d) [√2x-√3y=1 √x-2√2y-√5 (x+√3y=√(√2x+y=1-√10 √2x+√3y=√3 [(√2-1)x-y=√2 f) \x+(√2+1)y=1 9x-6y-15=0 g) √√√2x-2√3y = 5 h) 2x-11y=-7 (4x+7y=16 • 3√2x-√3y=4,5 i) 10x+11y=31 (0,35x + 4y = -2,6 j) 10x-9y=8 k) 0,75x-6y=9 15x+21y=0,5 4x-3y=-24 (3,3x+4,2y=1 9x+14y=4