Đáp án + Giải thích các bước giải:

$\begin{align}\textbf{1$\bigg)$ } 2x + \dfrac{1}{2} &= -\dfrac{5}{3} \\ 2x &= -\dfrac{5}{3} - \dfrac{1}{2} \\ 2x &= -\dfrac{13}{6} \\ x &= -\dfrac{13}{6} : 2 \\x &= -\dfrac{13}{12} \end{align}$

Vậy $x = -\dfrac{13}{12}$

$\begin{align}\textbf{5$\bigg)$ } 2x - \dfrac{3}{4} &= -\dfrac{5}{8} \\ 2x &= -\dfrac{5}{8} + \dfrac{3}{4} \\ 2x &= \dfrac{1}{8}\\ x &= \dfrac{1}{16}\end{align}$

Vậy $x = \dfrac{1}{16}$

$\begin{align}\textbf{9$\bigg)$ } \dfrac{3}{4}x - \dfrac{5}{2} &= \dfrac{4}{3} \\ \dfrac{3}{4}x &= \dfrac{4}{3} + \dfrac{5}{2} \\ \dfrac{3}{4}x &= \dfrac{23}{6}\\ x &= \dfrac{23}{6} : \dfrac{3}{4} \\ x &= \dfrac{46}{9} \end{align}$

Vậy $x = \dfrac{46}{9}$

$\begin{align}\textbf{13$\bigg)$ } -3x + \dfrac{1}{2} &= 2 - \dfrac{4}{3} \\ -3x + \dfrac{1}{2} &= \dfrac{2}{3} \\ -3x &= \dfrac{2}{3} - \dfrac{1}{2} \\ -3x &= \dfrac{1}{6} \\ x &= \dfrac{1}{6} : (-3) \\ x &= -\dfrac{1}{18} \end{align}$

Vậy $x = -\dfrac{1}{18}$

$\begin{align}\textbf{16$\bigg)$ } -2\dfrac{1}{3}x - 3\dfrac{1}{6} &= 1 - \dfrac{1}{2} \\ -\dfrac{7}{3}x - \dfrac{19}{6} &= \dfrac{1}{2} \\ -\dfrac{7}{3}x &= \dfrac{1}{2} + \dfrac{19}{6} \\ -\dfrac{7}{3}x &= \dfrac{11}{3} \\ x &= \dfrac{11}{3} : \bigg(-\dfrac{7}{3}\bigg) \\ x &= -\dfrac{11}{7} \end{align}$

Vậy $x = -\dfrac{11}{7}$

$\begin{align}\textbf{19$\bigg)$ } 2x - \dfrac{2}{3} - 7x &= \dfrac{3}{2} - 1 \\ -5x - \dfrac{2}{3} &= \dfrac{1}{2} \\ -5x &= \dfrac{1}{2} + \dfrac{2}{3} \\ -5x &= \dfrac{7}{6} \\ x &= \dfrac{7}{6} : (-5) \\ x &= -\dfrac{7}{30} \end{align}$

Vậy $x = -\dfrac{7}{30}$

$\begin{align}\textbf{22$\bigg)$ } 2x - \dfrac{1}{4} &= \dfrac{5}{6} - \dfrac{1}{2}x \\ 2x + \dfrac{1}{2}x &= \dfrac{5}{6} + \dfrac{1}{4} \\ \dfrac{5}{2}x &= \dfrac{13}{12} \\ x &= \dfrac{13}{12} : \dfrac{5}{2} \\ x &= \dfrac{13}{30} \end{align}$

Vậy $x =\dfrac{13}{30}$