Đáp án`+`Giải thích các bước giải:

 `11, (x - 1)^2+ 4x -4= 0`

`<=> (x - 1)^2 + 4(x - 1)= 0 `

`<=> (x - 1)(x - 1 +4) = 0`

`<=> (x - 1)(x + 3) = 0`

`<=>` $\left[\begin{matrix} x=1\\ x=-3\end{matrix}\right.$

Vậy `S= {1;-3}`

`12, (x - 4)^2 = 5x - 20`

`<=> (x - 4)^2 - 5(x - 4) = 0`

`<=> (x - 4)(x - 4 -5) = 0`

`<=> (x - 4)(x - 9) = 0`

`<=>` $\left[\begin{matrix} x=4\\ x=9\end{matrix}\right.$

Vậy `S= {4;9}`

`13, (2 - 3x)(x + 11) = (3x - 2)(2 - 5x)`

`<=> (2 - 3x)(x + 11) + (2 - 3x)(2 - 5x) = 0`

`<=> (2 - 3x)(x + 11 + 2 -5x) = 0`

`<=> (2 - 3x)(13 - 4x) = 0`

`<=>` $\left[\begin{matrix} x=\dfrac{2}{3}\\ x=\dfrac{13}{4}\end{matrix}\right.$

Vậy `S= {2/3;(13)/4}`

`14, (2x  - 1)^2 + (2 -x)(2x - 1) =0`

`<=> (2x - 1)(2x - 1 + 2 -x) =0`

`<=> (2x - 1)(x + 1) = 0`

`<=>` $\left[\begin{matrix} x=\dfrac{1}{2}\\ x=-1\end{matrix}\right.$

Vậy `S= {1/2;-1}`

`15, 2(3x + 1)^2 = (3x + 1)(x - 2)`

`<=> 2(3x + 1)^2 - (3x + 1)(x -2) = 0`

`<=> (3x + 1)[2(3x +1) - x + 2] = 0`

`<=> (3x + 1)(6x + 2 - x + 2) = 0`

`<=> (3x + 1)(5x + 4) = 0`

`<=>` $\left[\begin{matrix} x=\dfrac{-1}{3}\\ x=\dfrac{-4}{5}\end{matrix}\right.$

Vậy `S= {-1/3;-4/5}`

`16, -5(4x - 1) (x - 2) = 2(4x - 1)^2`

`<=> 2(4x-  1)^2 + 5(4x - 1)(x - 2) = 0`

`<=> (4x - 1)[2(4x - 1) + 5(x - 2)] = 0`

`<=> (4x - 1)(8x - 2 + 5x - 10) = 0`

`<=> (4x - 1)(13x - 12) = 0`

`<=>` $\left[\begin{matrix} x=\dfrac{1}{4}\\ x=\dfrac{12}{13}\end{matrix}\right.$

Vậy `S= {1/4;(12)/(13)}`

`***`sharksosad