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`1,`
`x-45 = 48-68`
`x-45 = -20`
`x = 25`
`2,`
`35 + 5.(6-x) = (-12) + |-112|`
`35 + 30 - 5x = -12 + 112`
`65 - 5x = 100`
`5x = 65 - 100`
`5x = -35`
`x = -7`
`3,`
`126 - 3.(x-9)`
`= 126 - 3x + 27`
`= 153 - 3x`
`4,`
`157 - (x - 124) = -483`
`157 - x + 124 = -483`
`-x + 181 = -483`
`-x = -664`
`x = 664`
`5,`
`46 - (3x-2)^2 = (-38) + 20`
`46 - (3x-2)^2 = -18`
`(3x-2)^2 = 64`
`TH1`
`3x-2 = 8`
`x = 10/3`
`TH2`
`3x-2 = -8`
`x = -2`
Vậy `x = {10/3 ; -2}`
`6,`
`13 - |x+6| = -7-10`
`13 - |x+6| = -17`
`|x+6| = 30`
`TH1`
`x+6 = 30`
`x = 24`
`TH2`
`x+6 = -30`
`x = -36`
Vậy `x = {24 ; -36}`
`7,`
`(2x-5)^3 = 15^2 - 4.5^2`
`(2x-5)^3 = 225 - 4.25`
`(2x-5)^3 = 225 - 100`
`(2x-5)^3 = 125`
`(2x-5)^3 = 5^3`
`=> 2x-5 = 5`
`<=> 2x = 10`
`<=> x = 5`
`8,`
`|16-x|-4 = 18-|12|`
`|16-x|-4 = 18-12`
`|16-x|-4 = 6`
`|16-x|=10`
`TH1`
`16-x = 10`
`x = 6`
`TH2`
`16-x = -10`
`x = 26`
Vậy `x = {6 ; 26}`
`9,`
`(x-2).(15-3x) = 0`
`TH1`
`x-2 = 0`
`x = 2`
`TH2`
`15-3x = 0`
`3x = 15`
`x = 5`
Vậy `x = {2 ; 5}`
`10,`
`117 - (x+5) = 26 + (-9)`
`117 - x - 5 = 26 - 9`
`112 - x = 17`
`x = 112 - 17`
`x = 95`
`11,`
`(x-5) - (2x+7) = -8`
`x-5 - 2x - 7 = -8`
`-12 - x = -8`
`x = -12 + 8`
`x = -4`
`12,`
`(x+1)+(x+2) + ... + (x+50) = 1475`
`(x+x+x+x+...+x)+(1+2+3+4+...+50) = 1475`
`50x + 1275 = 1475`
`50x = 200`
`x = 4`
`13,`
`x+(-36) = 33 - |-103|`
`x - 36 = 33 - 103`
`x - 36 = -70`
`x = -34`
`14,`
`[(8x-12):4].3^6 = 3^9`
`(8x-12):4 = 3^3`
`(8x-12):4 = 27`
`8x-12 = 27.4`
`8x-12 = 108`
`8x = 120`
`x = 15`
`15,`
`220 + [2^4 + (x-5)] = 8^2 . 5`
`2^4 + (x-5) = 320 - 220`
`16 + x - 5 = 100`
`x + 11 = 100`
`x = 89`
`16,`
`213 - (x-6) = 2136 : 12`
`213 - (x-6) = 178`
`x-6 = 213 - 178`
`x-6 = 35`
`x = 41`
`17,`
`3.(2x-1)^3 - 1^2020 = 5. 4^2`
`3.(2x-1)^3 - 1 = 5.16`
`3.(2x-1)^3 = 81`
`(2x-1)^3 = 27`
`(2x-1)^3 = 3^3`
`=> 2x-1 = 3`
`2x = 4`
`x = 2`
`18,`
`18 + |x+7| = 9 - (-11)`
`18 + |x+7| = 9+11`
`|x+7| = 2`
`TH1`
`x+7 = 2`
`x = -5`
`TH2`
`x+7 = -2`
`x = -9`
Vậy `x = {-5 ; -9}`
`19,`
`-x+5 = 3x + (-11)`
`-x-3x = -11 - 5`
`-4x = -16`
`x = 4`
`20,`
`2x+5+(x-7) = (-3)+22`
`2x+5+x-7 = 19`
`3x - 2 = 19`
`3x = 21`
`x = 7`
`21,`
`(x+4).(1+|x-2|) = 0`
`TH1`
`x+4 = 0`
`x = -4`
`TH2`
`1+|x-2| = 0`
`|x-2| = -1`
`=> x = 1` hoặc` x = 3`
Vậy `x = {-4 ; 1 ; 3}`
#Yoshimoto Shizuka
Hãy giúp mọi người biết câu trả lời này thế nào?
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Đáp án `+` Giải thích các bước giải:
Bài `4:`
`1) x - 45 = 48 - 68`
`x - 45 = -20`
`x = -20 + 45`
`x= 25`
``
`2) 35 + 5 . ( 6 − x ) = ( − 12 ) + | − 112 |`
`35 + 5 (6 - x) = -12 + 112`
`35 + 5 (6 -x ) = 100`
`5 (6 - x) = 100 -35`
`5 (6-x) = 65`
`6 - x = 65 : 5`
`6 - x = 13`
`x = 6 - 13`
`x = -7`
``
`3) 126 - 3 [x - 9]`
`= 126 - 3x + 27`
`= (126 + 27)- 3x`
`= 153 - 3x`
``
`4) 157 - (x - 124)= -483`
`x- 124 = 157 + 483`
`x - 124 = 640`
`x = 640 + 124`
`x = 764`
``
`5) 46 - (3x - 2)^2 = (-38) + 20`
`46 - (3x - 2)^2 = -18`
`(3x-2)^2 = 46 + 18`
`(3x - 2)^2 = 64`
`3x - 2 = - 8` hoặc `3x - 2 = 8`
`3x = - 8 + 2` `3x = 8 + 2`
`3x = -6` `3x = 10`
`x = -6 : 3` `x = 10 : 3`
`x = -2` `x = 10/3`
Vậy `x \in {-2; 10/3}`
``
`6) 13 - | x + 6| = - 7 - 10`
`13 - |x + 6| = -17`
`|x + 6| = 13 + 17`
`| x+ 6| = 30`
`x + 6 = -30` hoặc `x + 6 = 30`
`x = -30 - 6` `x = 30 - 6`
`x = -36` `x = 24`
Vậy `x \in {-36; 24}`
``
`7) (2x - 5)^3 = 15^2 - 4 . 5^2`
`(2x - 5)^3 = 225 - 4 . 25`
`(2x - 5)^3 = 225 - 100`
`(2x - 5)^3 = 125`
`2x - 5 = 5`
`2x = 5 + 5`
`2x = 10`
`x = 10 : 2`
`x = 5`
``
`8) |16 - x| - 4 = 18 - |12|`
`|16 - x| - 4 = 18 - 12`
`|16 - x| - 4= 6`
`|16 - x| = 6 + 4`
`|16 - x| = 10`
`16 - x = 10` hoặc `16 - x= -10`
`x= 16 - 10` `x = 16 + 10`
`x= 6` `x = 26`
Vậy `x \in {6; 26}`
``
`9) (x-2)(15 - 3x) = 0`
`x - 2 = 0` hoặc `15 - 3x = 0`
`x = 2` `3x = 15`
`x = 15 : 3`
`x = 5`
Vậy `x \in {2;5}`
``
`10) 117- (x+5) = 26 + (-9)`
`117 - (x+5) = 17`
`x + 5 = 117 - 17`
`x + 5 = 100`
`x = 100 - 5`
`x = 95`
``
`11) (x-5) - (2x + 7) = -8`
`x - 5 - 2x - 7 = - 8`
`(x - 2x) + (-5 - 7) = -8`
`-x - 12 = -8`
`-x = -8 + 12`
`-x = 4`
`x= -4`
``
`12) (x+1) + (x+2) + ... + (x + 50) = 1 475`
`x + 1 + x + 2 + ... + x + 50 = 1475`
`(x + x+ ... + x) + (1+ 2 + ... + 50) = 1475`
Ta có: `1 + 2 + ... + 50 = (50 xx (50 + 1))/2 = 1275`
`=> 50x + 1275 = 1475`
`50x = 200`
`x = 200: 50`
`x = 4`
``
`13) x + (-36) = 33 - |-103|`
`x + (-36) = 33 - 103`
`x + (-36) = -70`
`x = -70 + 36`
`x = -34`
``
`14) [(8x - 12) : 4] . 3^6 = 3^9`
`(8x - 12) : 4 = 3^9 : 3^6`
`(8x - 12) : 4 = 3^3 = 27`
`8x - 12 = 27 . 4`
`8x - 12 = 108`
`8x = 108 + 12`
`8x = 120`
`x = 120 : 8`
`x = 15`
``
`15) 220 + [2^4 + (x-5)]= 8^2 . 5`
`220 + [16 + (x-5)] = 64 . 5`
`220+[16+(x−5)]=320`
`16 + (x-5) = 320 - 220`
`16 + (x-5) = 100`
`x - 5 = 100 -16`
`x - 5 = 84`
`x = 84 + 5`
`x = 89`
``
`16) 213 − ( x − 6 ) = 2136 : 12`
`213 - (x - 6) = 178`
`x - 6 = 213 - 178`
`x - 6 = 35`
`x = 35 + 6`
`x = 41`
``
`17) 3 (2x -1)^3 - 1^2020 = 5 . 4^2`
`3 (2x - 1)^3 - 1 = 5 . 16`
`3 (2x - 1)^3 - 1 = 80`
`3 ( 2x - 1)^3 = 80 + 1`
`3 (2x - 1)^3 = 81`
`(2x- 1)^3 = 81 : 3`
`(2x-1)^3 = 27`
`2x - 1 = 3`
`2x = 3 + 1`
`2x= 4`
`x = 4 : 2`
`x = 2`
``
`18) 18 + | x + 7 | = 9 − ( − 11 )`
`18 + |x + 7| = 20`
`|x + 7| = 20 - 18`
`|x + 7| = 2`
`x + 7 = 2` hoặc `x + 7 =- 2`
`x = 2 - 7` `x = -2 - 7`
`x = -5` `x = -9`
Vậy `x \in {-5; -9}`
``
`19) − x + 5 = 3 x + ( − 11 )`
`-x - 3x = -5 - 11`
`-4x = -16`
`x = -16 : (-4)`
`x = 4`
``
`20) 2 x + 5 + ( x − 7 ) = ( − 3 ) + 22`
`2x + 5 + x - 7 = 19`
`(2x + x)+ (5 - 7) = 19`
`3x -2 = 19`
`3x = 19 + 2`
`3x = 21`
`x = 21 : 3`
`x = 7`
``
`21) ( x + 4 ) . ( 1 + | x − 2 | ) = 0`
`x + 4 = 0` hoặc `1 + |x - 2| = 0`
`x = -4` `∣x−2∣≥0⇒1+∣x−2∣≥1 → x \in ∅`
Vậy `x = -4`
Hãy giúp mọi người biết câu trả lời này thế nào?
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làm xong mất hết não
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=)))
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mà thầy ở âm phủ vui vẻ chứ
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nịt m á
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ơ kìa thầy sao lại chửi em ;-;
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.-.
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;-;
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._.