Giải thích các bước giải:

a.$(4x^5-8x^3):(-2x^3)=-2x^2+4$

b.$(9x^3-12x^2+3x):(-3x)=-3x^2+4x-1$

c.$(xy^2+4x^2y^3-3x^3y^4):(-2xy^2)=-\dfrac12-2xy+\dfrac32x^2y^2$

d.$(-3x^2y^3+4x^3y^4-y^4y^5):(-x^2y^3)=3-4xy+\dfrac{y^6}{x^2}$

e.$(2(x-y)^3-7(y-x)^2-(y-x)):(x-y)=-2(x-y)^2-7(x-y)+1$

f.$(3(x-y)^5-2(x-y)^4+3(x-y)^2):(5(x-y)^2)$

$=\dfrac35(x-y)^3-\dfrac25(x-y)^2+\dfrac35$