Thể tích lều `a` là :

`V_1=350.460.180+(1/2).350.40.460=32200000\text{ cm}^3`

`S_{BCED}=210.260=54600(cm^2)`

`S_{ABC}=1/2\(260-210).260=6500(cm^2)`

`S_{BDF}=1/2\.210.\frac{370-260}2=5775(cm^2)`

`S_{\text{mặt trước}}=54600+6500+2.5775=72650(cm^2)`

Thể tích lều `b` là:

`V_2=72650.430=31239500(cm^3)`

`->V_1-V_2=32200000-31239500\approx961 dm^3`