`a)` Đúng

`b)` Sai

`c)` Sai

`DHA: C_{21}H_{31}COOH`

`EPA: C_{19}H_{29}COOH`

`n_{C_3H_5(OH)_3} = (8,28)/(92) = 0,09 (mol)`

`m_{\text{chất béo}} = 100 - 100.8,86\% = 91,14 (g)`

BTKL: `m_{NaOH} = 93,935 + 8,28 - 91,14 = 11,075 (g)`

`n_{NaOH} = (11,075)/(40) = 0,276875(mol)`

`n_{Acid} = n_{NaOH(acid)} = 0,276875 - 0,09.3 = 6,875.10^{-3} (mol)`

Chỉ số acid là: `(6,875.10^{-3} . 56.1000)/(100) = 3,85`

`d)` Sai

Xét `100(gam)X`

Đặt `n_{DHA} = a (mol); n_{EPA} = b (mol)`

`n_{C_{21}H_{31}COONa} = n_{DHA} = a (mol)`

`n_{C_{19}H_{29}COONa} = n_{EPA} = b (mol)`

`a + b = 0,276875`

`350a + 324b = 93,935`

`=> a = (1691)/(10400); b = (2377)/(20800)`

`m_{DHA} = 0,4.10^6 . 12\% = 48000(g)`

`m_{EPA} = 0,4.10^6 . 18\% = 72000(g)`

Tính theo DHA: `m_X = (48000)/( (1691)/(10400) . 328) .(0,1)/(80\%)= 113(kg)`

Tính theo EPA: `m_X = (72000)/( (2377)/(20800) .302) . (0,1)/(80\%) = 261(kg)`