Đáp án:

B

Lời giải:

`\int ([\sqrt(x)(x+1)]dx)`

`=\int (x\sqrt(x)+\sqrt(x))dx`

`=\int (x\sqrt(x))dx + \int (\sqrt(x))dx`

`=\int (x^(3/2))dx + \int (x^(1/2))dx`

`=x^(5/2) /(5/2) + x^(3/2) / (3/2) +C`

`=2/5 .x^2\sqrt(x) + 2/3 .x\sqrt(x) + C`

`=\sqrt(x) (2/5 x^2 + 2/3 x) +C`.