Đáp án:

Giải thích các bước giải:

Câu 4:

n_(H_2SO_4)=m/M=(19,6)/98=0,2(mol)

a) PTHH

    H_2SO_4+Ba(OH)_2->BaSO_4downarrow+H_2O

b)  0,2                ->                0,2                                                     (mol)

Từ PTHH => m_(BaSO_4)=M.n=233.0,2=46,6(g)

Câu 5:

\begin{array}{|c|c|c|}\hline \text{Chất}&\text{Phân loại}&\text{Tên gọi}\\\hline \text{BaO}&\text{Oxide base}&\text{Barium oxide}\\\hline \text{Cu(OH)2}&\text{Base}&\text{Copper (II) hydroxide}\\\hline \text{H2SO4}&\text{Acid}&\text{Sulfuric acid}\\\hline \text{HCl}&\text{Acid}&\text{Hydrochloric acid}\\\hline \text{KOH}&\text{Base}&\text{Potassium hydroxide}\\\hline \text{CO2}&\text{Oxide acid}&\text{Carbon dioxide}\\\hline \text{Fe2O3}&\text{Oxide base}&\text{Iron (III) oxide}\\\hline \text{P2O5}&\text{Oxide acid}&\text{Diphosphorus pentoxide}\\\hline \text{NaOH}&\text{Base}&\text{Sodium hydroxide}\\\hline \text{CH3COOH}&\text{Acid}&\text{Acetic acid}\\\hline\end{array}