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Đáp án:
Giải thích các bước giải:
$CH_3COONa+$$NaOH$$\longrightarrow$$CH_4$+$Na_2$$CO_3$
$2CH_4$$\longrightarrow$$C_2$$H_2$+$3H_2$
$C_2$$H_2$+$H_2$ $\longrightarrow$ $C_2$$H_4$
$C_2$$H_4$+$Cl_2 \longrightarrow$ $C_2$$H_4$$Cl_2$
$C_2$$H_4$$Cl_2$+$2NaOH$ $\longrightarrow$ $C_2$$H_4$$(OH)_2$+$2NaCl$
$Cu(OH)_2$+$C_2$$H_4$$(OH)_2$$\longrightarrow$$(C_2$$H_4(OH)O$)$_2Cu$+$2H_2O$
$C_2$$H_2$+$H_2O$$\longrightarrow$$CH_3CHO$
$CH_3CHO+$$3I_2$+$4NaOH$$\longrightarrow$$CHI_3$+$HCOONa$+$3NaI$+$3H_2O$
$C_2$$H_2$+$2H_2$$\longrightarrow$$C_2$$H_6$
$C_2$$H_6$+$Cl_2$ $\longrightarrow$ $C_2$$H_5$$Cl$+$HCl$
$C_2$$H_5$$Cl$+$NaOH$ $\longrightarrow$ $C_2$$H_5$$OH$+$NaCl$
$C_2$$H_5$$OH$+$CuO$$\longrightarrow$$Cu$+$CH_3CHO$+$H_2O$
$CH_3CHO$+$2AgNO_3$+$3NH_3$+$H_2O$$\longrightarrow$$CH_3COONH_4$+$2NH_4$$NO_3$+$2Ag$
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$\rm (1) CH_3COONa+NaOH \xrightarrow{CaO,t^o} CH_4+ Na_2CO_3 $
$\rm (2) 2CH_4 \xrightarrow{làm lạnh nhanh, t^o} C_2H_2+3H_2$
$\rm (3)C_2H_2+H_2O \xrightarrow{HgSO_4,H_2SO_4đ}CH_3CHO$
$\rm (4)CH_3CHO+3I_2+4NaOH \to HCOONa+CHI_3+3NaI+3H_2O$
$\rm (5)C_2H_2+2H_2 \xrightarrow{t^o,Ni} C_2H_6$
$\rm (6) C_2H_6+ Cl_2 \xrightarrow{as} C_2H_5Cl+HCl$
$\rm (7) C_2H_5Cl+2KOH \xrightarrow{t^o} C_2H_5OH+2KCl$
$\rm (8) CH_3CH_2OH+CuO \xrightarrow{t^o} CH_3CHO+Cu+H_2O$
$\rm (9) CH_3CHO+2[Ag(NH_3)_2]OH \xrightarrow{t^o} CH_3COONH_4+2Ag+2NH_4NO_3+H_2O$
$\rm (10) C_2H_2+H_2 \xrightarrow{t^o, Lindlar} C_2H_4$
$\rm (11)CH_2=CH_2+Cl_2 \xrightarrow{t^o,as} CH_2Cl-CH_2Cl$
$\rm (12) 3C_2H_4+2KMnO_4+4H_2O \xrightarrow{t^o} 3C_2H_4(OH)_2+2MnO_2+2KOH$
không có phản ứng từ $\rm C_2H_4Cl_2 \to C_2H_4(OH)_2$
$\rm (13)C_2H_4(OH)_2+Cu(OH)_2 \to [C_2H_4(OH)O]_2Cu+2H_2O$
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