`\color{pink}\text{@nguyenphuannam}`

`a)2AgNO_3+BaCl_2->2AgCl↓+Ba(NO_3)_2`

`b)n_(AgNO_3)=C_M.V=0,1.0,1=0,01(mol)` 

`n_(AgCl)=(0,01.2)/2=0,01(mol)`

`m_AgCl=n_(AgCl).M_(AgCl)=0,01.143,5=1,435(g)`

`c)n_(BaCl_2)=(0,01)/2=0,005(mol)`

`C_MBaCl_2=(n_(BaCl_2))/(V_(BaCl_2))=(0,005)/(0,025)=0,2M`