Sos cứu mik v ạ mai nộp cho thầy rùi

`a)` `-2x-3(x+2)=4`

`-2x-3x-6=4`

`-5x-6=4`

`-5x=4+6`

`-5x=10`

`x=10:(-5)`

`x=-2`

Vậy `x=-2`

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`b)` `3(2x-1)-5(x-3)+6(3x-4)=24`

`6x-3-5x+15+18x-24=24`

`(6x-5x+18x)+(-3+15-24)=24`

`19x-12=24`

`19x=24+12`

`19x=36`

`x=36/19`

Vậy `x=36/19`

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`c)` `2x^2+3(x^2-1)-5x(x+1)=0`

`2x^2+3x^2-3-5x^2-5x=0`

`(2x^2+3x^2-5x^2)-5x-3=0`

`-5x-3=0`

`-5x=0+3`

`-5x=3`

`x=-3/5`

Vậy `x=-3/5`

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`d)` `2x(x-1)-x(x-2)=4`

`2x^2-2x-x^2+2x=4`

`(2x^2-x^2)+(-2x+2x)=4`

`x^2=4`

TH`1:` `x^2=2^2`

`=>x=2`

TH`2:` `x^2=(-2)^2`

`=>x=-2`

Vậy `x\in {2;-2}`