Giải giúp mình với ạ

2.

`C_2H_5OH+3O_2` $\xrightarrow{t^o}$ `2CO_2+3H_2O`

`->\Delta_r H_{298}^0=5.413+467+347+358+3.498-2.2.745-3.2.467=-1051(kJ)`

`n_{C_2H_5OH}={{2.90}/{100}.0,8}/{46}={18}/{575}(mol)`

Lượng nhiệt tỏa ra là `{18}/{575}.1051\approx 32,9(kJ)`

3.

`n_{H_2}={3718,5.10^{-3}}/{24,79}=0,15(mol)`

`C_2H_5OH+Na->C_2H_5ONa+1/2H_2`

`C_6H_5OH+Na->C_6H_5ONa+1/2H_2`

`C_6H_5OH+NaOH->C_6H_5ONa+H_2O`

Theo PT: `n_{C_6H_5OH}=n_{NaOH}=0,2.1=0,2(mol)`

`->n_{C_2H_5OH}=2n_{H_2}-n_{C_6H_5OH}=0,1(mol)`

`->m=0,1.46+0,2.94=23,4(g)`

4.

`n_{CH_3COOH}={2.1000.6\%.1,05}/{60}=2,1(mol)`

`CH_3COOH+NaOH->CH_3COONa+H_2O`

`2,1->2,1(mol)`

`->V={2,1}/{0,5}=4,2(L)`