Giải thích các bước giải:

d.$8x-8x^3-10x^2+3x^4-5$ 

$=x^2(3x^2-2x+1)-2x(3x^2-2x+1)-5(3x^2-2x+1)$

$=(x^2-2x-5)(3x^2-2x+1)$

$\to (8x-8x^3-10x^2+3x^4-5):(3x^2-2x+1)=x^2-2x-5$

e.$(x^5+x^3+x^2+1):(x^3+1)$

$=((x^5+x^2)+(x^3+1)):(x^3+1)$

$=(x^2(x^3+1)+(x^3+1)):(x^3+1)$

$=(x^2+1)(x^3+1):(x^3+1)$

$=x^2+1$