Đáp án$+$Giải thích các bước giải:

`2y(x-3)=x+2`

`=>` `2y(x-3)-(x-3)=5`

`=>` `(x-3)(2y-1)=5`

`=>` `x-3;2y -1\in Ư(5)={ -5;-1;1;5}`

Ta có bảng sau:

\begin{array}{|c|c|c|}\hline \text{x-3}&\text{-5}&\text{-1}&\text{1}&\text{5}\\\hline \text{2y-1}&\text{-1}&\text{-5}&\text{5}&\text{1}\\\hline \text{x}&\text{-2}&\text{2}&\text{4}&\text{8}\\\hline \text{y}&\text{0}&\text{-2}&\text{3}&\text{1}\\\hline\end{array}