Đáp án`+`Giải thích các bước giải:

`2y(x-3)=x+2`

`<=> 2y(x-3)-(x-3)=5`

`<=> (x-3)(2y-1)=5`

`=> x-3;2y -1 \in Ư_{(5)}={ -5;-1;1;5}`

Ta có bảng:

\begin{array}{|c|c|c|}\hline \text{x-3}&\text{-5}&\text{-1}&\text{1}&\text{5}\\\hline \text{2y-1}&\text{-1}&\text{-5}&\text{5}&\text{1}\\\hline \text{x}&\text{-2}&\text{2}&\text{4}&\text{8}\\\hline \text{y}&\text{0}&\text{-2}&\text{3}&\text{1}\\\hline\end{array}