Mn giúp em với!!!!!!

Đáp án: $2030$

Giải thích các bước giải:

Ta có:

$P(x)-Q(x)=(7x^8-6x^5+2x^4-3x+1)-(x^8-6x^5+2x^4-3x-2023)$

$\to P(x)-Q(x)=6x^8+2024$

Ta có:

$\dfrac{2023\cdot 2024+1}{2024+2023^2}\cdot (x+2)=3$

$\to \dfrac{2023\cdot (2023+1)+1}{2024+2023^2}\cdot (x+2)=3$

$\to \dfrac{2023^2+2023+1}{2024+2023^2}\cdot (x+2)=3$

$\to \dfrac{2023^2+2024}{2024+2023^2}\cdot (x+2)=3$

$\to x+2=3$

$\to x=1$

$\to P(1)-Q(1)=6\cdot 1^8+2024=2030$