Giải phương trình ….

`@ Alana`

`f)` $\dfrac{x+15}{2035}$ `+`$\dfrac{x+20}{2030}$ `+`$\dfrac{x+25}{2025}$ `=`$\dfrac{x+30}{2020}$ `+`$\dfrac{x+35}{2015}$ `+`$\dfrac{x+40}{2010}$

  `=>` $\dfrac{x+15}{2035}$`+1 +`$\dfrac{x+20}{2030}$`+1+`$\dfrac{x+25}{2025}$`+1 =`$\dfrac{x+30}{2020}$`+1+`$\dfrac{x+35}{2015}$`+1+`$\dfrac{x+40}{2010}$`+1`

`=>`$\dfrac{x+15+2035}{2035}$ `+`$\dfrac{x+20+2030}{2030}$ `+`$\dfrac{x+25+2025}{2025}$ `=`$\dfrac{x+30+2020}{2020}$ `+`$\dfrac{x+35+2015}{2015}$ `+`$\dfrac{x+40+2010}{2010}$

`=>` $\dfrac{x+2050}{2035}$ `+`$\dfrac{x+2050}{2030}$ `+`$\dfrac{x+2050}{2025}$ `=`$\dfrac{x+2050}{2020}$ `+`$\dfrac{x+2050}{2015}$ `+`$\dfrac{x+2050}{2010}$

`=>` $\dfrac{x+2050}{2035}$ `+`$\dfrac{x+2050}{2030}$ `+`$\dfrac{x+2050}{2025}$ `-`$\dfrac{x+2050}{2020}$ `-`$\dfrac{x+2050}{2015}$ `-`$\dfrac{x+2050}{2010}$ `=0`

`=> (x+2050)(`$\dfrac{1}{2035}$ `+`$\dfrac{1}{2030}$ `+`$\dfrac{1}{2025}$ `-`$\dfrac{1}{2020}$ `-`$\dfrac{1}{2015}$ `-`$\dfrac{1}{2010}$ `) = 0`

Mà `(`$\dfrac{1}{2035}$`+`$\dfrac{1}{2030}$`+`$\dfrac{1}{2025}$`-`$\dfrac{1}{2020}$`-`$\dfrac{1}{2015}$`-`$\dfrac{1}{2010}$`)` khác `0`

`=> x +2050 = 0`

`x = - 2050`

Vậy pt này có nghiệm là `-2050`