hãy giúp tuiii vớiii huhu

`1` `bbD`

`2` `bbC`

Nhân hai lũy thừa cùng cơ số: `a^m*b^m=(ab)^m`

`3` `bbC`

`4`

`(1/16)^[-0.75]+(1/8)^[-4/3]`

`= (2^[-4])^[-0.75]+(2^[-3])^[-4/3]`

`= 2^3+2^4`

`= 8+16`

`= 24`

`-> bbD`

`5`

`P=x^[1/3]*root[6][x] (x>0)`

`P=x^[1/3]*x^[1/6]`

`P=x^[1/3+1/6]`

`P=x^[1/2]`

`P=sqrtx`

`-> bbC`

`6`

Có `a^[1/2]>a^[1/6] -> a>1`

`b^[sqrt2]>b^[sqrt3] -> 0<b<1`

`-> bbA`

`7` `bbA`

Với `a ne1` thì `log_a a=1`

`8`

`log_3 (9a) (a>0)`

`= log_3 9+log_3 a`

`= log_3 3^2+log_3 a`

`= 2+log_3 a`

`-> bbD`

`9`

`ln(7a)-ln(3a) (a>0)`

`= [ln(7a)]/[ln(3a)]`

`-> bbD`

`10`

`log_3 (3/a) (a>0)`

`= log_3 3-log_3 a`

`= 1-log_3 a`

`-> bbD`

`11`

`y=log_2 (2-3x)`

HSXĐ `-> 2-3x>0 -> x<2/3`

TXĐ: `D=(-infty; 2/3)`

`-> bbC`