`#` Ta có ` : `

$\left.\begin{array}{l}6x^3 - 7x^2 - x + 2\\\ \ -4x^2 - x + 2\\\quad-3x + 2\\\qquad -x + 1\end{array}\right|\!\!\!\;\!\!\begin{array}{l}\dfrac{\ \ 2x - 1\ \ }{\ \ 3x^2 - 2x - 1\ \ }\\\\\\\end{array}$

Vậy ` : ... `