giúp mik bài này vs ạ

`1, 2x^2 - 7x+ 3 = 0`

`<=> 2x^2 - x - 6x + 3 = 0`

`<=> x(2x-1) - 3(2x - 1) = 0`

`<=> (2x-1)(x-3) = 0 `

`<=> [( x = 1/2),(x =3):}`

`2 Q =  ( [sqrtx + 3]/[sqrtx - 2] - [sqrtx - 3]/[sqrtx + 2] ) : sqrt[25x]/[sqrtx + 2] - sqrtx/[sqrtx - 2] ( x > 0 ; x ne 4)`

`= [(sqrtx + 3)(sqrtx + 2) - (sqrtx - 3)(sqrtx - 2)]/[x-4] . [sqrtx + 2]/[5sqrtx] - sqrtx/[sqrtx -2]`

`= [x +5sqrtx +6 - x + 5sqrtx - 6]/[sqrtx - 2] . 1/[5sqrtx] - sqrtx/[sqrtx - 2]`

`= [10sqrtx]/[sqrtx - 2] . [5sqrtx] - sqrtx/[sqrtx -2]`

`= 2/[sqrtx - 2] - sqrtx/[sqrtx - 2]`

`= [2-sqrtx]/[sqrtx - 2] = -1`