PTHH:
$\rm (1), CH≡C-CH_3+AgNO_3+NH_3\to CAg≡C-CH_3\downarrow +NH_4NO_3\\ (2) CH_2=CH-CH_3+H_2O\xrightarrow{H_3PO_4,t^o} CH_3-CH(OH)-CH_3\\ (3) CH_3-CH=CH_2+H_2O \xrightarrow{t^o,xt}$ \(\left[ \begin{array}{l}CH_3-CH_2-CH_2-OH(\text{sản phẩm phụ})\\CH_3-CH(OH)-CH_3(\text{sản phẩm chính})\end{array} \right.\) $ \\ (4) CH_2=CH-CH_2-CH_3+HCl\xrightarrow{xt} $\(\left[ \begin{array}{l}Cl-CH_2-CH_2-CH_2-CH_3(\text{sản phẩm phụ})\\CH_3-CHCl-CH_2-CH_3(\text{sản phẩm chính})\end{array} \right.\) $\\ (5) CH_2=C(CH_3)-CH_3 +H_2O\xrightarrow{H_3PO_4,t^o} CH_3-C(OH)(CH_3)-CH_3 \\ (6) C_6H_5-CH_3+3HNO_3(đ)\xrightarrow{t^o}  C_6H_5-CH_3(NO_2)_3+3H_2O \\ (7) CH_2=CH-CH_3+H_2\xrightarrow{t^o,Ni} CH_3-CH_2-CH_3 \\ (8) C_6H_5-CH=CH_2+Br_2\xrightarrow{CCl_4} C_6H_5-CHBr-CHBr_2\\ (8?)C_6H_5-CH=CH_2+Br_2\xrightarrow{Fe,H_2O,1:1} C_6H_4(Br)-CHBr-CHBr_2+HBr(\text{Br} thế chủ yếu vào ortho, para)$