Đáp án:

`b) (x-10)/30 + (x-14)/43 + (x-5)/95 + (x-148)/8 = 0`

    `(x-10)/30 + (x-14)/43 + (x-5)/95 + (x-148)/8 - 6 + 6 = 0`

    `((x-10)/30 - 3) + ((x-14)/43-2) + ((x-5)/95-1) + (x-148)/8 + 6 = 0`

    `(x-100)/30 + (x-100)/43 + (x-100)/95 + (x-100)/8 = 0`

    `(x-100)*(1/30 + 1/43 + 1/95 + 1/8) = 0`

Mà `1/30 + 1/43 + 1/95 + 1/8 \ne 0`

`=>` `x-100=0`

`=>` `x=100`

Vậy `x=100`

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