Giải hộ em bài 1vaf2 với ạ

`#Tran`

`"Bài 1:"`

`a)`

`27^(2/3) + 81^(-0,75) - 25^(-0,5)`

`= (3^3)^(2/3) + 1/(81^(3/4)) - 1/((25)^(1/2))`

`=3^2 + 1/((3^4)^(3/4)) - 1/5`

`=9 + 1/27 - 1/5`

`=(1193)/(135)`

`b)`

`A=27^(2/3) + (1/(16))^(-0,75) - 36^(-0,5) + sqrt2^0`

`=(3^3)^(2/3) + (16)^(0,75) - 1/(6^2)^(1/2) + 1`

`=3^2 + (2^4)^(3/4) - 1/6 + 1`

`=9 + 8 -1/6 + 1`

`=(107)/6`

`c)`

`3^(3+sqrt2). 3^(-1+sqrt2). 9^(1-sqrt2)`

`=3^(3+sqrt2). 3^(-1+sqrt2). 3^(2-2sqrt2)`

`=3^(3+sqrt2-1+sqrt2+2-2sqrt2)`

`=3^4`

`=81`

`d)`

`A= ((a^(sqrt2-1))^(1+sqrt2))/(a^(sqrt5-1)/a^(3-sqrt5))`

`=(a^((sqrt2-1)(1+sqrt2)))/(a^2)`

`=a/(a^2)`

`=1/a`

`e)`

`A=log_2 (x^3-x) - log_2 (x+1) - log_2 (x-1)` `(x-1)`

`=log_2 (x^3-x) - log_2 (x+1)(x-1)`

`=log_2 (x(x+1)(x-1))/((x+1)(x-1))`

`=log_2 x`

`f)`

`log_4 48 - log_4 3`

`=log_4 (48)/3`

`=log_4 6`

`g)`

`4log_(12) 2 + 2log_(12) 3`

`=2log_(12) 4 + 2log_(12) 3`

`=2log_(12) 12`

`=2`

________________________________________

`"Bài 2:"`

`a)` 

`16^sqrt3=(4^2)^sqrt3=4^(2sqrt3)=4^sqrt12`

`4^(3sqrt2)=4^sqrt18`

Do `12 < 18` 

nên `4^sqrt12 < 4^sqrt18`

hay `16^sqrt3 < 4^(3sqrt2)`

`b)`

`(0,2)^sqrt16= (0,2)^4=(0,2)^∛(64)`

`(0,2)^∛(60)`

Do `64 > 60`

nên `∛(64) > ∛(60)`

mà `0,2 < 1`

nên `(0,2)^∛(64) < (0,2)^∛(60)`

hay `(0,2)^sqrt16 < (0,2)^∛(60)`