

Tìm x thuộc Z , sao cho :
a) (x-1)mũ 2 = 1
b) 7 mũ 2x-6 = 49
c) (2x-16) mũ 7 = 128
d) 565 - 13 . x = 370
e) 105 - ( 135 -7x) : = 97
f) 275- (113+x) +63 = 158
g) [ 3. (x+2) : 7 ] . 4 = 120
h) x(x-1)=0
i) (x+2)(x-4)=0
k) (x-140) : 7 = 3 mũ 3 - 2 mũ 3 . 3
l) x^3 . x^2 = 2^8 : 2^3
m)3^x-3^2 = 2.3^2
Cuu tớ vs aa =>>
Hãy luôn nhớ cảm ơn và vote 5*
nếu câu trả lời hữu ích nhé!
`#khanhly2949`
`a,`
`(x-1)^2=1`
`th_1 : (x-1)^2=1^2`
`=>x-1=1`
`=>x=2`
`th_2 : (x-1)^2=(-1)^2`
`=>x-1=-1`
`=>x=0`
Vậy `x\in{2;0}`
`b,`
`7^(2x-6)=49`
`=>7^(2x-6)=7^2`
`=>2x-6=2`
`=>2x=8`
`=>x=4`
Vậy `x=4`
`c,`
`(2x-16)^7=128`
`=>(2x-16)^7=2^7`
`=>2x-16=2`
`=>2x=18`
`=>x=9`
Vậy `x=9`
`d,`
`565-13 . x=370`
`=>13 . x=565-370`
`=> 13. x =195`
`=>x=195 : 13`
`=>x=15`
Vậy `x=15`
`e,`
`105-(135-7x) : 9=97`
`=>(135-7x):9=105-97`
`=>(135-7x):9=8`
`=>135-7x=72`
`=>7x=63`
`=>x=9`
Vậy `x=9`
`f,`
`275-(113+x)+63=158`
`=>275-113-x+63=158`
`=>-x=-275+113-63+158`
`=>-x=-67`
`=>x=67`
Vậy `x=67`
`g,`
`[3(x+2) : 7] . 4=120`
`=>3(x+2) : 7=30`
`=>3(x+2)=210`
`=>x+2=70`
`=>x=68`
Vậy `x=68`
`h,`
`x(x-1)=0`
`th_1 : x=0`
`th_2 : x-1=0`
`=>x=1`
Vậy `x\in{0;1}`
`i,`
`(x+2)(x-4)=0`
`th_1 : x+2=0`
`=>x=-2`
`th_2 : x-4=0`
`=>x=4`
Vậy `x\in{-2;4}`
`k,`
`(x-140) : 7=3^3-2^3 . 3`
`=>(x-140) : 7=27-8 . 3`
`=>(x-140) : 7=3`
`=>x-140=21`
`=>x=161`
Vậy `x=161`
`l,`
`x^3 . x^2=2^8 : 2^3`
`=>x^5 =2^5`
`=>x=2`
Vậy `x=2`
`m,`
`3^x -3^2=2 . 3^2`
`=>3^x-9=2 . 9`
`=>3^x-9=18`
`=>3^x=27`
`=>3^x=3^3`
`=>x=3`
vậy `x=3`
Hãy giúp mọi người biết câu trả lời này thế nào?

`a)`
`(x-1)^2=1`
`Th1:`
`x-1=1`
`x=1+1`
`x=2`
`Th2:`
`x-1=-1`
`x=-1+1`
`x=0`
Vậy `x in {2;0}`
`b)`
`7^(2x-6)=49`
`7^(2x-6)=7^2`
`2x-6=2`
`2x=8`
`x=4`
Vậy `x=4`
`c)`
`(2x-16)^7=128`
`(2x-16)^7=2^7`
`2x-16=2`
`2x=18`
`x=9`
Vậy `x=9`
`d)`
`565-13x=370`
`13x=565-370`
`13x=195`
`x=195÷13`
`x=15`
Vậy `x=15`
`e)`
`105-(135-7x)÷9=97`
`(135-7x)÷9=105-97`
`(135-7x)÷9=8`
`135-7x=8·9`
`135-7x=72`
`7x=135-72`
`7x=63`
`x=9`
Vậy `x=9`
`f)`
`275-(113+x)+63=158`
`275-(113+x)=158-63`
`275-(113+x)=95`
`113+x=275-95`
`113+x=180`
`x=180-113`
`x=67`
Vậy `x=67`
`g)`
`[3(x+2)÷7]·4=120`
`3(x+2)÷7=30`
`3(x+2)=210`
`x+2=70`
`x=68`
Vậy `x=68`
`h)`
`x(x-1)=0`
`x=0` hoặc `x-1=0`
`x=0` hoặc `x=1`
Vậy `x in {0;1}`
`i)`
`(x+2)(x-4)=0`
`x+2=0` hoặc `x-4=0`
`x=-2` hoặc `x=4`
Vậy `x in {-2;4}`
`k)`
`(x-140)÷7=3^3-2^3·3`
`(x-140)÷7=27-8·3`
`(x-140)÷7=27-24`
`(x-140)÷7=3`
`x-140=21`
`x=161`
Vậy `x=161`
`l)`
`x^3·x^2=2^8÷2^3`
`x^5=2^5`
`x=2`
Vậy `x=2`
`m)`
`3^x-3^2=2·3^2`
`3^x-9=2·9`
`3^x-9=18`
`3^x=27`
`3^x=3^3`
`x=3`
Vậy `x=3`
Hãy giúp mọi người biết câu trả lời này thế nào?

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