Giúp toooooooooooooooo

Đáp án+Giải thích các bước giải:

a) Với ` x \ne 0 ; x \ne +- 2 ; x \ne - 1/2` ta có:

`2/x + 5/( x - 2) - 3/(2x + 1) - 2/x + 3/(2x + 1) - 5/( x + 2)`

`= (2/x - 2/x) + (5/( x - 2) - 5/( x + 2))+ (- 3/(2x + 1) + 3/(2x + 1))`

`= 0 + (5( x + 2))/(( x -2)( x + 2)) - (5( x - 2))/(( x - 2)( x + 2)) + 0`

`= (5x + 10 - 5x + 10)/(( x - 2)( x + 2))`

`= 20/(( x - 2)( x + 2))`

 b) Với ` x \ne 0 ; x \ne +- 4 ; x \ne - 3/2` ta có:

`(3x - 1)/x + (- x + 2)/(2x + 3) - ( x + 2)/(x^2 - 16) + ( 1 - 3x)/x - ( 2 - x)/(2x + 3) + 1/( x - 4)`

`= ( (3x - 1)/x + ( 1 - 3x)/x ) + ( ( - x + 2)/(2x + 3)  - (2 - x)/(2x + 3 ) + ( - (x + 2)/(x^2 - 16) + 1/( x - 4) )`

`= ( 3x - 1 + 1 - 3x)/x + (- x + 2 - 2 + x)/(2x + 3) + ( - ( - x + 2))/((x - 4)( x + 4)) + (x+ 4)/(( x - 4)( x + 4))`

`= 0 + 0 + (  x -  2 + x + 4)/((x -4)( x + 4))`

`= (2x + 2)/(x^2 - 16)`