Ai giúp em với ạ ,em đang cần gấp

Cảm ơn ạ

b/`|x+1/1.4|+|x+1/4.7|+|x+1/7.10|+...|x+1/70.73|=25x(x>=0)`

Vì `x>=0` nên `{(|x+1/1.4|=(x+1/1.4)),(|x+1/4.7|=(x+1/4.7)),(|x+1/7.10|=(x+1/7.10)),(...),(|x+1/70.73|=(x+1/70.73)):}`

Ta có:`(x+1/1.4)+(x+1/4.7)+(x+1/7.10)+...+(x+1/70.73)=25x`

`x+1/1.4+x+1/4.7+x+1/7.10+...+x+1/70.73=25x`

`(x+x+x+...+x)+(1/1.4+1/4.7+1/7.10+...+1/70.73)=25x`

`24x+1/3.(3/1.4+3/4.7+3/7.10+...+3/70.73)=25x`

`24x+1/3.(1-1/4+1/4-1/7+1/7-1/10+...+1/70-1/73)=25x`

`24x+1/3.(1-1/73)=25x`

`24x+1/3. 72/73=25x`

`24x+24/73=25x`

`25x-24x=24/73`

`x=24/73`(tmđk)

Vậy `x=24/73`