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Bài `1:`
`a) ((-7)/12+0,25) :2/3`
`= (-7/12+1/4) :2/3`
`= (-7/12+3/12) :2/3`
`= -1/3:2/3`
`= -1/3*3/2`
`= -1/2`
`b) sqrt{4/9} +((-1)/2)^3 - |(-3)/11| * 11/8`
`= 2/3 - 1/8 - 3/11 * 11/8`
`= 2/3 - 1/8 - 3/8`
`= 2/3 - 1/2`
`= 1/6`
`c) 5/6 - 2021^0 + (3/2)^2 : |(-9)/4| + sqrt{25/9}`
`= 5/6-1+9/4:9/4+5/3`
`= 5/6-1+1+5/3`
`= 5/6+5/3`
`= 5/2`
`d) 2022-(-7/121)^0 + (-1/3)^2 . 9`
`= 2022-1+1/9*9`
`= 2022-1+1`
`= 2022`
`e) (6^13 - 3 . 6^12 + 3^13)/(9^5(4^6 + 1))`
`= ((2.3)^13 - 3 . (2.3)^12 +3^13)/(9^5(4^6+1))`
`= (2^13 . 3^13 - 3 . 2^12 . 3^12 + 3^13)/(9^5(4^6+1))`
`= (2^13 . 3^13 - 3^13 . 2^12 + 3^13)/(9^5(4^6+1))`
`= (3^13(2^13 - 2^12+1))/(9^5(4^6+1))`
`= (3^13(2^13 - 2^12+1))/((3^2)^5(2^13-2^12+1))`
`= (3^13(2^13-2^12+1))/(3^10(2^13-2^12+1))`
`= 3^3=27`
`f) (27^15 + 27^5)/(27^14+9^6)`
`= ((3^3)^15 + (3^3)^5)/((3^3)^14 + (3^2)^6)`
`= (3^45 + 3^15)/(3^42 + 3^12)`
`= (3^15(3^30+1))/(3^12(3^30+1))`
`= 3^3=27`
`\ttcolor{#00FF00}{#}\ttcolor{#00EE00}{b}\ttcolor{#00DD00}{u}\ttcolor{#00CC00}\ttcolor{#00BB00}{i}\ttcolor{#00AA00}{g}\ttcolor{#009900}{i}\ttcolor{#008800}{a}\ttcolor{#007700}{p}\ttcolor{#006600}{h}\ttcolor{#005500}{o}\ttcolor{#004400}{n}\ttcolor{#003300}\ttcolor{#002200}{g}\ttcolor{#001100}{999}`
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