`lim [-2+3n-2n^3]/[3n-2]`

`= lim [n^3(-2/[n^3]+3/[n^2]-2)]/[n(3-2/n)]`

`= lim [n^2(-2/[n^3]+3/[n^2]-2)]/[3-2/n]`

Nhận xét

`lim n^2=+infty`

`lim [-2/[n^3]+3/[n^2]-2]/[3-2/n]=[0+0-2]/[3-0]=-2/3<0`

`-> lim [-2+3n-2n^3]/[3n-2]=-infty`