Đáp án+Giải thích các bước giải:

`n_(CH_3COOC_2H_5)=44/(12+1*3+12+16+16+12*2+1*5)=0,5(mol)`

`PTHH:C_2H_5OH+CH_3COOH` $\buildrel{{H_2SO_4(đ);t^0}}\over\rightleftharpoons$ `CH_3COOC_2H_5+H_2O` 

`@` Theo `PTHH=>n_(C_2H_5OH)=n_(CH_3COOC_2H_5)=0,5(mol)`

`=>m_(C_2H_5OH)=0,5*(12*2+1*5+16+1)=23(g)`

`@` Theo `PTHH=>n_(CH_3COOH)=n_(CH_3COOC_2H_5)=0,5(mol)`

`=>m_(CH_3COOH)=0,5*(12+1*3+12+16+16+1)=30(g)`

$---------------$

`@text{Công thức tính:}`

`+)n=m/M=>m=M*n`

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