$\frac{x+2023}{2}$ + $\frac{2x+4046}{3}$ = $\frac{x+2023}{5}$ + $\frac{3x+6069}{7}$ 

$\frac{x+2023}{2}$ + $\frac{2.(x+2023)}{3}$ = $\frac{x+2023}{5}$ + $\frac{3.(x+2023)}{7}$ 

(x+2023).($\frac{1}{2}$ +$\frac{2}{3}$ - $\frac{1}{5}$ - $\frac{3}{7}$)

->x+2023=0 [vì ($\frac{1}{2}$ +$\frac{2}{3}$ - $\frac{1}{5}$ - $\frac{3}{7}$) ≠ 0]

->x= 0 - 2023

->x= -2023

Vậy -> x= -2023