a, PTHH:

`2CH_3COOH+2Na\to 2CH_3COONa+H_2`

`n_{H_2}=(2,479)/(24,79)=0,1\ (mol)`

b, Theo PT:

`n_{CH_3COOH}=2n_{H_2}=0,2\ (mol)`

`\to m=m_{CH_3COOH}=0,2.60=12\ (g)`

c, Trung hoà `CH_3COOH`:

`CH_3COOH+NaOH\to CH_3COONa+H_2O`

Theo PT:

`n_{NaOH]=n_{CH_3COOH}=0,2\ (mol)`

`\to V_{dd\ NaOH}=(0,2)/1=0,2\ (l)`