`m_{\text{tristearin}}=1.89\%=0,89(\text{tấn})`
PTHH:
`(C_{17}H_{35}COO)_3C_3H_5+3NaOH\to 3C_{17}H_{35}COONa+C_3H_5(OH)_3`
`=>m_{C_{17}H_{35}COONa(\text{lý thuyết})}= (0,89)/(890) . 306 .3= 0,918(\text{tấn})`
`=>m_{C_{17}H_{35}COONa(\text{thực tế})}= 0,918. 85\% =0,7803(\text{tấn})`
`=>m_{\text{xà phòng}}=0,7803 : 75\%\approx 1,04(\text{tấn})`