giúp em làm với ạaaa

`a,` Ta có `m_{\text{1 hạt e}}=9,109.10^{-27}(g)`

`=>N_e=(1)/(9,109.10^{-27})\approx 1,097.10^{26}(\text{hạt})`

`b,` `1(mol)` electron

`=>N_e=1.6,022.10^{23}=6,022.10^{23}(\text{hạt})`

`=>m_e=6,022.10^{23}.9,109.10^{-27}=5,485.10^{-3}(g)`