`n) (1/2+1/3+...+1/2014)x=2013/1+2012/2+...+1/2013`

`=> (1/2+1/3+...+1/2014)x= (2014-1)/1+(2014-2)/2+...+(2014-2013)/2013`

`=> (1/2+1/3+...+1/2014)x= 2014/1-1+2014/2-1+...+2014/2013-1`

`=> (1/2+1/3+...+1/2014)x= (2014/1+2014/2+...+2014/2013)-(1+1+1+....+1)(2013` số `1)`

`=> (1/2+1/3+...+1/2014)x= 2014(1+1/2+...+1/2013)-2013`

`=> (1/2+1/3+...+1/2014)x= 2014(1/2+1/3+...+1/2013+1/2024)+2014-1-2013`

`=> (1/2+1/3+...+1/2014)x=2014(1/2+1/3+...+1/2014)`

Vậy `x=2014`