$\color{lightblue}{\text{o Lâm Vũ}}$

Tìm `x`:

$\dfrac{60}{2}$ : `15` + `0,5` + $\dfrac{1}{3}$ + $\dfrac{60}{2}$ : `x`

`30` : `15` + `0,5` + $\dfrac{1}{3}$ + `30` : `x`

`2` + `0,5` + $\dfrac{1}{3}$ + $\dfrac{30}{x}$ 

$\dfrac{12}{6}$ + $\dfrac{1}{2}$ + $\dfrac{2}{6}$ + $\dfrac{30}{x}$

$\dfrac{12}{6}$ + $\dfrac{3}{6}$ * $\dfrac{2}{6}$ + $\dfrac{30}{x}$

$\dfrac{12 + 3 + 2}{6}$ + $\dfrac{30}{x}$

$\dfrac{17}{6}$ + $\dfrac{30}{x}$ = `0`

$\dfrac{30}{x}$ = -$\dfrac{17}{6}$

`30` . `6` = `-17` . `x`

`180` = `-17x`

`x` = `180` : `17`

=> `x` = $\dfrac{-180}{17}$

Vậy x = $\dfrac{-180}{17}$