x+5/x^2-5x - x+25/2x^2-50 = x-5/2x^2+10x

`@` ĐKXĐ: `x ne{0;+-5}`

`(x+5)/(x^2-5x) - (x+25)/(2x^2-50) = (x-5)/(2x^2+10x)`

`<=>(x+5)/(x(x-5))-(x+25)/(2(x-5)(x+5))=(x-5)/(2x(x+5))`

`<=>(2(x+5)^2)/(2x(x-5)(x+5))-(x(x+25))/(2x(x-5)(x+5))=(x-5)^2/(2x(x-5)(x+5))`

`<=>2(x^2+10x+25)-(x^2+25x)=x^2-10x+25`

`<=>2x^2+20x+50-x^2-25x-x^2+10x-25=0`

`<=>5x=-25`

`<=>x=-5(Loại)`

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