Đáp án+Giải thích các bước giải:

`sin(2x-\pi/4)=sin(x+(3\pi)/4)`

`⇔[(2x-\pi/4=x+(3\pi)/4+k2\pi),(2x-\pi/4=\pi-(x+(3\pi)/4)+k2\pi):}`      `k inZ`

`⇔[(2x=x+\pi+k2\pi),(2x=\pi/2-x+k2\pi):}`

`⇔[(x=\pi+k2\pi),(3x=\pi/2+k2\pi):}`

`⇔[(x=\pi+k2\pi),(x=\pi/6+(k2\pi)/3):}`

Vậy `S={\pi+k2\pi;\pi/6+(k2\pi)/3|k inZ}`