Anh chị xin dừng bước giúp thiếu nữ đang ngã vào hố sìn vớiii

a)$\left \{ {{x^2-x} \atop {x-1}} \right.$ 

=$\left \{ {{x(x-1)} \atop {x.(x-1)}} \right.$ 

MTC:x(x-1)

d)$\left \{ {{x-2} \atop {x+1}} \right.$ 

=$\left \{ {{(x-2).(x+1)} \atop {(x+1).(x-2)}} \right.$ 

 MTC:(x-2)(x+1)

g)$\left \{ {{x^2-5x} \atop {5x-25}} \right.$ 

=$\left \{ {{x(x-5)} \atop {5(x-5)}} \right.$ 

=$\left \{ {{5.x(x-5)} \atop {5.x.(x-5)}} \right.$ 

MTC:5x(x-5)

b)$\left \{ {{x^2-9} \atop {x+3}} \right.$

=$\left \{ {{(x+3)(x-3)} \atop {(x+3).(x-3)}} \right.$ 

MTC:(x+3)(x-3)

e)$\left \{ {{x^3-8} \atop {x-2}} \right.$ 

=$\left \{ {{(x-2)(x^2+2x+4)} \atop {(x-2).(x^2+2x+4)}} \right.$ 

MTC:(x-2)(x^2+2x+4)

h) x³-1

    x²+x+1

    x-1

=(x-1)(x²+x+1)

   (x²+x+1).(x-1)

   (x-1).(x²+x+1)

MTC:(x-1)(x²+x+1)

c)$\left \{ {{x} \atop {x^2+2x}} \right.$ 

=$\left \{ {{x.(x+2)} \atop {x(x+2)}} \right.$ 

MTC:x(x+2)

f)4x²-1

  2x-1

  2x+1

=(2x-1)(2x+1)

   (2x-1).(2x+1)

   (2x+1)(2x-1)

MTC:(2x-1)(2x+1)