`A = 2 cos 60^o - 2 sin 30^o + cot 45^o`

`= 2 . 1/2 - 2 . 1/2 + 1`

`= 1 - 1 + 1`

`= 1`

Vậy `A = 1`

$\\$

`B = cos45^o + tan30^o . sin60^o`

`= \sqrt{2}/2 + 1/\sqrt{3} . \sqrt{3}/2`

`= \sqrt{2}/2 + 1/2`

`= (\sqrt{2} + 1)/2`

Vậy `B=(\sqrt{2} + 1)/2`