Làm hết hộ mik cảm ơn nhìu

`a)` `(1/2-2x)^3=8/125`

`=>(1/2-2x)^3=(2/5)^3`

`=>1/2-2x=2/5`

`=>2x=1/10`

`=>x=1/20`

Vậy `x=1/20`$\\$

`b)` `(12 7/8-10 13/18):x-1 7/33:8/11=1 2/3`

`=>155/72:x-5/3=5/3`

`=>155/72:x=10/3`

`=>x=31/48`

Vậy `x=31/48`$\\$

`c)` `(1-3/10-x):(19/10-1-2/5)+4/5=1`

`=>(7/10-x):1/2=1/5`

`=>7/10-x=1/10`

`=>x=3/5`

Vậy `x=3/5`$\\$

`d)` `(3/4x-2)^2=25/49`

`=>3/4x-2=5/7` hoặc `3/4x-2=-5/7`

`=>3/4x=19/7` hoặc `3/4x=9/7`

`=>x=76/21` hoặc `x=12/7`

Vậy `x in{76/21;12/7}`