Giúp với akk, m cam on rất nhìu

`\frac{1}{6}-\frac{4}{3}:\frac{6}{7}<x<(-\frac{2}{5}-\frac{-5}{3}). \frac{6}{5}`

`<=>`$\left[\begin{matrix} \frac{1}{6}-\frac{4}{3}:\frac{6}{7}<x\\x<(-\frac{2}{5}-\frac{-5}{3}). \frac{6}{5}\end{matrix}\right.$

`<=>`$\left[\begin{matrix} \frac{1}{6}-\frac{14}{9}<x\\x<\frac{19}{15}. \frac{6}{5}\end{matrix}\right.$

`<=>`$\left[\begin{matrix} -\frac{25}{18}<x\\x<\frac{38}{25}\end{matrix}\right.$

`<=>-\frac{25}{18}<x<\frac{38}{25}`

Vậy `x in {-25/18;38/25}`