`(2\sqrt{x}-2)/(\sqrt{x}-3) <0` (ĐKXĐ: `x>=0`)

Dễ thấy `2\sqrt{x}-2 > \sqrt{x}-3`

Để `(2\sqrt{x}-2)/(\sqrt{x}-3) <0`

`⇔ {(2\sqrt{x}-2>0),(\sqrt{x}-3<0):}`

`⇔ {(x>1),(0<x<9):}`

`⇔ 1<x<9`

Vậy,..

`color{purple}{@SHIN}`