Đáp án:

` [(x=0),(x=19/10):}`

Giải thích các bước giải:

`(8x-3)(3x+2)-(4x+7)(x+4)=(2x+1)(5x-1)-33`

`⇔(8x.3x+8x.2-3.3x-3.2)-(4x.x+7.x+4x.4+7.4)=(2x.5x+5x-2x-1)-33`

`⇔(24x^2+7x-6)-(4x^2+23x+28)=(10x^2+3x-1)-33`

`⇔24x^2+7x-6-4x^2-23x-28-10x^2-3x+34=0`

`⇔(24x^2-4x^2-10x^2)+(7x-23x-3x)+(34-6-28)=0`

`⇔10x^2-19x=0`

`⇔x(10x-19)=0`

`⇔[(x=0,(10x-19=0):}`

`⇔[(x=0),(x=19/10):}`

Vậy `[(x=0),(x=19/10):}`