Help meee. Too dag cần gấpp aa🫰

Đáp án:

Giải thích các bước giải:

`a)(-6)/(x+3) = 2/3` `(x` $\ne$ `-3)`

`<=>(-6.3)/(3(x+3))  =(2(x+3))/(3(x+3))`

`<=>-6.3=2(x+3)`

`<=>-18=2x+6`

`<=>-2x=6+18`

`<=>-2x=24`

`<=>x=(24)/(-2)`

`<=>x=-12` (tmđkxđ)

Vậy `S={-12}`

`c)8/(3x-4)=1/(x+2)` `(x` $\ne$ `4/3;-2)`

`<=>(8(x+2))/((3x-4)(x+2)) = (3x-4)/((3x-4)(x+2))`

`<=>8(x+2)=3x-4`

`<=>8x+16=3x-4`

`<=>8x-3x=-4-16`

`<=>5x=-20`

`<=>x=(-20)/5`

`<=>x=-4` (tmđkxđ)

Vậy `S={-4}`

`e)(3x-2)/(x+1) =4- (x+2)/(x-1)` `(x` $\ne$ `-1;1)`

`<=>((3x-2)(x-1))/((x+1)(x-1)) = (4(x-1)(x+1))/((x-1)(x+1)) - ((x+2)(x+1))/((x-1)(x+1))`

`<=>(3x-2)(x-1)=4(x-1)(x+1)-(x+2)(x+1)`

`<=>3x^2-3x-2x+2=4(x^2-1)-(x^2+x+2x+2)`

`<=>3x^2-5x+2=4x^2-4-x^2-x-2x-2`

`<=>3x^2-5x-4x^2+x^2+x+2x=-4-2-2`

`<=>(3x^2-4x^2+x^2)+(-5x+x+2x)=-8`

`<=>-2x=-8`

`<=>x=(-8)/(-2)`

`<=>x=4` (tmđkxđ)

Vậy `S={4}`