Giải giúp mk hứa sẽ vote5 sao ạ

Đặt `AH=x (x>0) =>BH=60-x`

Xét `ΔAHC` có:

`CH = AH.tan20^o = x.tan20^o`

Xét `ΔBHC` có:

`CH = BH.tan30^o = (60-x).tan30^o`

`=>x.tan20^o=(60-x).tan30^o`

`=>xtan20^o = 60tan30^o -xtan30^o`

`=>xtan20^o+ xtan30^o = 60tan30^o`

`=>x(tan20^o+tan30^o) = 60tan30^o`

`=>x =  (60tan30^o)/(tan20^o+tan30^o)`

`=>x≈36,8`

`=>AH=36,8`

`BH=60-36,8=23,2`

`CH=36,8 tan20^o = 13,4`

Vậy `AH=36,8 ; BH=23,2 ; CH=13,4`