`( 1/2 )^24` và `( 1/3 )^36`

`( 1/2 )^24 = ( 1/2 )^( 2 . 12 ) = [( 1/2 )^2 ]^12 = ( 1/4 )^12`

`( 1/3 )^36 = ( 1/3 )^( 3 . 12 ) + [( 1/3 )^3 ]^12 = ( 1/27 )^12`

`-> 1/4 > 1/27`

`-> ( 1/4 )^12 > ( 1/27 )^12`

`-> ( 1/2 )^24 > ( 1/3 )^36`

Vậy `( 1/2 )^24 > ( 1/3 )^36`

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`( 1/5 )^50` và `( 1/3 )^75`

`( 1/5 )^50 = ( 1/5 )^( 2 . 25 ) = [( 1/5 )^2 ]^25 = ( 1/25 )^25`

`( 1/3 )^75 = ( 1/3 )^( 3 . 25 ) = [( 1/3 )^3 ]^25 = ( 1/27 )^25`

`-> 1/25 > 1/27`

`-> ( 1/25 )^25 > ( 1/27 )^25`

`-> ( 1/5 )^50 > ( 1/3 )^75`

Vậy `( 1/5 )^50 > ( 1/3 )^75`

`---`

`( - 1/2 )^300` và `( - 1/3 )^200`

`( - 1/2 )^300 = ( 1/2 )^300 = ( 1/2 )^( 3 . 100 ) = [( 1/2 )^3 ]^100 = ( 1/8 )^100`

`( - 1/3 )^200 = ( 1/3 )^200 = ( 1/3 )^( 2 . 100 ) = [( 1/3 )^2 ]^100 = ( 1/9 )^100`

`-> 1/8 > 1/9`

`-> ( 1/8 )^100 > ( 1/9 )^100`

`-> ( - 1/2 )^300 > ( - 1/3 )^200`

Vậy `( - 1/2 )^300 > ( - 1/3 )^200`

`#`Nguyencanhthinh`#`

`*** Hoidap247`