`@` `\color{Silver}{\text{πk2}`

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`h)(3x-5)·6x·(2x+7)=0`

`⇒`\(\left[ \begin{array}{l}3x-5=0\\6x=0\\2x+7=0\end{array} \right.\)

`⇒`\(\left[ \begin{array}{l}x=\frac{5}{3}\\x=0\\x=\frac{-7}{2}\end{array} \right.\)

Vậy `x∈{5/3;0;(-7)/2}`

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`i)1/5((-3)/10-10)+5x=x-2/3`

`⇒1/5((-3)/10-100/10)+5x-x+2/3=0`

`⇒1/5·(-103)/10+4x+2/3=0`

`⇒(-103)/50+2/3+4x=0`

`⇒(-309)/150+100/150+4x=0`

`⇒(-209)/150+4x=0`

`⇒4x=(209)/150`

`⇒x=(209)/1500:4`

`⇒x=(209)/150·1/4`

`⇒x=(209)/600`

Vậy `x=(209)/600`